IIF X AND Y , why does Y get evaluated?

I have some logic in a report that is not working as I thought it should and
it puzzles me.
Lets says I have this line, (ignoring syntax errors, I forget what is
supposed to be there for days)
IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8, SomeDate))
Now because in this case ProductType is 5, SomeDate isn't populated, its
null if this language has that concept. But the error I get is telling me
that adding -8 to SomeDate produces something thats not a date. Well of
course thats true because when ProductType is 5 and SomeDate is nothing so
why is it even looking at it.
Is there a way around this?
thanksOn Apr 12, 4:22 pm, "Coaster" <Coas...@.Coaster.net> wrote:
> I have some logic in a report that is not working as I thought it should and
> it puzzles me.
>
That's weird, I would not have expected IIF to evaluate both branches,
but maybe if you first check SomeDate to see if it is null, then you
can control when DateAdd is run, like so:
IIF(Fields!ProductType.Value = 5,"Hello there", IIF
IsNull(SomeDate)=False, DateAdd(days, -8, SomeDate), ''))
HTH
> Lets says I have this line, (ignoring syntax errors, I forget what is
> supposed to be there for days)
> IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8, SomeDate))
> Now because in this case ProductType is 5, SomeDate isn't populated, its
> null if this language has that concept. But the error I get is telling me
> that adding -8 to SomeDate produces something thats not a date. Well of
> course thats true because when ProductType is 5 and SomeDate is nothing so
> why is it even looking at it.
> Is there a way around this?
> thanks|||On Apr 14, 4:59 am, "Jerry H." <boilersr...@.gmail.com> wrote:
> On Apr 12, 4:22 pm, "Coaster" <Coas...@.Coaster.net> wrote:> I have some logic in a report that is not working as I thought it should and
> > it puzzles me.
> That's weird, I would not have expected IIF to evaluate both branches,
> but maybe if you first check SomeDate to see if it is null, then you
> can control when DateAdd is run, like so:
> IIF(Fields!ProductType.Value = 5,"Hello there", IIF
> IsNull(SomeDate)=False, DateAdd(days, -8, SomeDate), ''))
>
I dont know if it resolves your issue or not . as per my experience,in
iif statement, then clause and else clause should have the same
datatype values,in the following case.one is date type and another is
string type .please correct this also
Thanks
Raj deep.A
>
> > Lets says I have this line, (ignoring syntax errors, I forget what is
> > supposed to be there for days)
> > IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8, SomeDate))
> > Now because in this case ProductType is 5, SomeDate isn't populated, its
> > null if this language has that concept. But the error I get is telling me
> > that adding -8 to SomeDate produces something thats not a date. Well of
> > course thats true because when ProductType is 5 and SomeDate is nothing so
> > why is it even looking at it.
> > Is there a way around this?
> > thanks|||I've seen today a coworker using IIF to avoid a division by zero error and
it seemed to works fine..
What is the error you get ? I suspect a problem with DateAdd (are you sure
"day" shouldn't be within quotes ?)
--
Patrice
"Coaster" <Coaster@.Coaster.net> a écrit dans le message de news:
ObHp0uNnIHA.1052@.TK2MSFTNGP05.phx.gbl...
>I have some logic in a report that is not working as I thought it should
>and it puzzles me.
> Lets says I have this line, (ignoring syntax errors, I forget what is
> supposed to be there for days)
> IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8,
> SomeDate))
> Now because in this case ProductType is 5, SomeDate isn't populated, its
> null if this language has that concept. But the error I get is telling me
> that adding -8 to SomeDate produces something thats not a date. Well of
> course thats true because when ProductType is 5 and SomeDate is nothing so
> why is it even looking at it.
> Is there a way around this?
> thanks
>|||On Apr 12, 4:22=A0pm, "Coaster" <Coas...@.Coaster.net> wrote:
> I have some logic in a report that is not working as I thought it should a=nd
> it puzzles me.
> Lets says I have this line, (ignoring syntax errors, I forget what is
> supposed to be there for days)
> IIF(Fields!ProductType.Value =3D 5,"Hello there", DateAdd(days, -8, SomeDa=te))
> Now because in this case ProductType is 5, SomeDate isn't populated, its
> null if this language has that concept. But the error I get is telling me
> that adding -8 to SomeDate produces something thats not a date. Well of
> course thats true because when ProductType is 5 and SomeDate is nothing so=
> why is it even looking at it.
> Is there a way around this?
> thanks
This is a quote from Chris Hayes from Microsoft:
"The problem is this: The IIF function evaluates all of its
arguments."
JerryH's solution (I adjusted his SQL to SSRS/VB syntax),
IIF(Fields!ProductType.Value =3D 5,"Hello there", IIF(SomeDate =3D
Nothing, Nothing, DateAdd("d", -8, SomeDate)))
may work because the nested IIf is evaluated first.
In the Code tab/window of Report Properties, enter the following:
Public Function DateMinus8(ByVal Exp1)
If Exp1 =3D 5 Then
DateMinus8 =3D "Hello There"
Else DateMinus8 =3D DateAdd("d", -8, SomeDate)
End If
End Function
Then use =3Dcode.DateMinus8(Fields!ProductType.Value )
instead of =3D IIF(Fields!ProductType.Value =3D 5,"Hello there",
DateAdd(days, -8, SomeDate))
To Patrice: I think your co-worker just got lucky and had no zeros
show up in the denominator because IIF will not resolve divide by zero
issues without some tweaking.
To truly avoid divide by zero use either:
Public Function DivideBy(ByVal Exp1, ByVal Exp2)
If Exp2 =3D 0 Then
DivideBy =3D 0
Else DivideBy =3D Exp1 / Exp2
End If
End Function
Then use =3Dcode.DivideBy(Numerator,Denominator)
instead of =3DIIF(Denominator =3D 0, 0, Numerator/Denominator)
OR if you don't want to use custom code try
=3DIIf(Denominator =3D 0, "N/A", Numerator / IIf(Denominator =3D 0, 1,
Denominator))|||On Apr 14, 12:46=A0pm, "Patrice" <http://www.chez.com/scribe/> wrote:
> I've seen today a coworker using IIF to avoid a division by zero error and=
> it seemed to works fine..
> What is the error you get ? I suspect a problem with DateAdd (are you sure=
> "day" shouldn't be within quotes ?)
> --
> Patrice
> "Coaster" <Coas...@.Coaster.net> a =E9crit dans le message de news:
> ObHp0uNnIHA.1...@.TK2MSFTNGP05.phx.gbl...
>
> >I have some logic in a report that is not working as I thought it should
> >and it puzzles me.
> > Lets says I have this line, (ignoring syntax errors, I forget what is
> > supposed to be there for days)
> > IIF(Fields!ProductType.Value =3D 5,"Hello there", DateAdd(days, -8,
> > SomeDate))
> > Now because in this case ProductType is 5, SomeDate isn't populated, its=
> > null if this language has that concept. But the error I get is telling m=e
> > that adding -8 to SomeDate produces something thats not a date. Well of
> > course thats true because when ProductType is 5 and SomeDate is nothing =so
> > why is it even looking at it.
> > Is there a way around this?
> > thanks- Hide quoted text -
> - Show quoted text -
This is a quote from Chris Hayes from Microsoft:
"The problem is this: The IIF function evaluates all of its
arguments."
JerryH's solution (I adjusted his SQL to SSRS/VB syntax),
IIF(Fields!ProductType.Value =3D 5,"Hello there", IIF(SomeDate =3D
Nothing, Nothing, DateAdd("d", -8, SomeDate)))
may work because the nested IIf is evaluated first.
I usually use custom code to get around the IIF issue. You could try
something like the following.
In the Code tab/window of Report Properties, enter the following:
Public Function DateMinus8(ByVal Exp1)
If Exp1 =3D 5 Then
DateMinus8 =3D "Hello There"
Else DateMinus8 =3D DateAdd("d", -8, SomeDate)
End If
End Function
Then use =3Dcode.DateMinus8(Fields!ProductType.Value )
instead of =3D IIF(Fields!ProductType.Value =3D 5,"Hello there",
DateAdd(days, -8, SomeDate))
To Patrice: I think your co-worker just got lucky and had no zeros
show up in the denominator because IIF will not resolve divide by
zero
issues without some tweaking.
To truly avoid divide by zero use either:
Public Function DivideBy(ByVal Exp1, ByVal Exp2)
If Exp2 =3D 0 Then
DivideBy =3D 0
Else DivideBy =3D Exp1 / Exp2
End If
End Function
Then use =3Dcode.DivideBy(Numerator,Denominator)
instead of =3DIIF(Denominator =3D 0, 0, Numerator/Denominator)
OR if you don't want to use custom code try
=3DIIf(Denominator =3D 0, "N/A", Numerator / IIf(Denominator =3D 0, 1,
Denominator))|||"toolman" <timd@.infocision.com> wrote in message
news:f3db3d38-59d5-402d-9b4b-e2b59c64f563@.u69g2000hse.googlegroups.com...
On Apr 12, 4:22 pm, "Coaster" <Coas...@.Coaster.net> wrote:
> I have some logic in a report that is not working as I thought it should
> and
> it puzzles me.
> Lets says I have this line, (ignoring syntax errors, I forget what is
> supposed to be there for days)
> IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8,
> SomeDate))
> Now because in this case ProductType is 5, SomeDate isn't populated, its
> null if this language has that concept. But the error I get is telling me
> that adding -8 to SomeDate produces something thats not a date. Well of
> course thats true because when ProductType is 5 and SomeDate is nothing so
> why is it even looking at it.
> Is there a way around this?
> thanks
This is a quote from Chris Hayes from Microsoft:
"The problem is this: The IIF function evaluates all of its
arguments."
JerryH's solution (I adjusted his SQL to SSRS/VB syntax),
IIF(Fields!ProductType.Value = 5,"Hello there", IIF(SomeDate =Nothing, Nothing, DateAdd("d", -8, SomeDate)))
may work because the nested IIf is evaluated first.
In the Code tab/window of Report Properties, enter the following:
Public Function DateMinus8(ByVal Exp1)
If Exp1 = 5 Then
DateMinus8 = "Hello There"
Else DateMinus8 = DateAdd("d", -8, SomeDate)
End If
End Function
Then use =code.DateMinus8(Fields!ProductType.Value )
instead of = IIF(Fields!ProductType.Value = 5,"Hello there",
DateAdd(days, -8, SomeDate))
To Patrice: I think your co-worker just got lucky and had no zeros
show up in the denominator because IIF will not resolve divide by zero
issues without some tweaking.
To truly avoid divide by zero use either:
Public Function DivideBy(ByVal Exp1, ByVal Exp2)
If Exp2 = 0 Then
DivideBy = 0
Else DivideBy = Exp1 / Exp2
End If
End Function
Then use =code.DivideBy(Numerator,Denominator)
instead of =IIF(Denominator = 0, 0, Numerator/Denominator)
OR if you don't want to use custom code try
=IIf(Denominator = 0, "N/A", Numerator / IIf(Denominator = 0, 1,
Denominator))
Thanks alot !!! I 'll check it out tomorrow at work. I didn't even know you
could have functions like that in the report. JerryH's solution didn't work
for me because it still evaluated the date even though it was nested,
hopefully this won't happen using a function.|||"Jerry H." <boilersrock@.gmail.com> wrote in message
news:8bd61d4f-5c11-434e-931b-0615c09fd011@.59g2000hsb.googlegroups.com...
> On Apr 12, 4:22 pm, "Coaster" <Coas...@.Coaster.net> wrote:
>> I have some logic in a report that is not working as I thought it should
>> and
>> it puzzles me.
> That's weird, I would not have expected IIF to evaluate both branches,
> but maybe if you first check SomeDate to see if it is null, then you
> can control when DateAdd is run, like so:
> IIF(Fields!ProductType.Value = 5,"Hello there", IIF
> IsNull(SomeDate)=False, DateAdd(days, -8, SomeDate), ''))
> HTH
>
>
>> Lets says I have this line, (ignoring syntax errors, I forget what is
>> supposed to be there for days)
>> IIF(Fields!ProductType.Value = 5,"Hello there", DateAdd(days, -8,
>> SomeDate))
>> Now because in this case ProductType is 5, SomeDate isn't populated, its
>> null if this language has that concept. But the error I get is telling me
>> that adding -8 to SomeDate produces something thats not a date. Well of
>> course thats true because when ProductType is 5 and SomeDate is nothing
>> so
>> why is it even looking at it.
>> Is there a way around this?
>> thanks
>
yeah it is weird and it even evaluated it in your solution. Perhaps the
toolmans solution will work. Find out tomorrow.|||Humm... I gave this a try on another report i'm working on :
=IIf(True,1,0/0)
and it worked fine. If I change True to False I then have a "non numerical
value" string shown in the field...
I'm using RS 2005...